All topics

s4.5.6

Minimal and Maximum Value of Expressions

1,000 questions

To find the minimum or maximum value of an expression, calculus (finding the derivative and setting it to zero) can be a slow method. It's often faster to use algebraic manipulation, such as completing the square.

For an expression like 2(x1)2+32(x-1)^2 + 3, the minimum value occurs when the squared term is zero, since squares are always non-negative. The minimum value of (x1)2(x-1)^2 is 0, so the minimum of the whole expression is 2(0)+3=32(0)+3=3.

For expressions with trigonometric functions, remember that the minimum value of sin and cos is -1, and the maximum is 1.

Practise this