Sum of the Squares of Arbitrary Fibonacci Sequence

To find the sum of the squares of the first $n$ terms of an Arbitrary Fibonacci Sequence ($A_1^2 + A_2^2 + \dots + A_n^2$), the formula is:

Sum of Squares = $A_n \times A_{n+1} - A_1(A_2 - A_1)$

For the Standard Fibonacci Sequence, where $A_1=1$ and $A_2=1$, the formula simplifies to $F_n \times F_{n+1}$ because the second term becomes zero.

For example, $1^2 + 1^2 + 2^2 + \dots + 34^2$ (the first 9 terms of the standard sequence) is $F_9 \times F_{10} = 34 \times 55 = 1870$.