Vertex of a Parabola

For a parabola given by the equation $f(x) = Ax^2 + Bx + C$, the coordinates of the vertex $(h, k)$ can be found using the formula:

$h = -\frac{B}{2A}$

Once you find the x-coordinate, $h$, you can find the y-coordinate, $k$, by substituting $h$ back into the function: $k = f(h)$.

For example, to find the y-coordinate of the vertex of $y = 3x^2 - 12x + 16$:
$x = -\frac{-12}{2 \cdot 3} = 2$.
$y = 3(2)^2 - 12(2) + 16 = 12 - 24 + 16 = 4$.