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s1.3.7

Multiplying Two Numbers Ending in 5

1,000 questions

When multiplying two numbers that both end in 5 (e.g., a5a5 and b5b5), there is a specific trick based on whether the sum of the leading digits (a+ba+b) is even or odd.

  • If a+ba+b is even, the last two digits of the answer are 25.
  • If a+ba+b is odd, the last two digits of the answer are 75.

The rest of the answer is found by calculating a×b+a+b2a \times b + \lfloor \frac{a+b}{2} \rfloor.

For 45×8545 \times 85: a+b=4+8=12a+b = 4+8=12 (even), so the end is 25. The rest is 4×8+122=32+6=384 \times 8 + \frac{12}{2} = 32+6 = 38. Answer: 3825.

For 35×8535 \times 85: a+b=3+8=11a+b = 3+8=11 (odd), so the end is 75. The rest is 3×8+112=24+5=293 \times 8 + \lfloor \frac{11}{2} \rfloor = 24+5 = 29. Answer: 2975.

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